18x^2=-9x

Solution for 18x^2=-9x equation:

18x^2=-9x

We move all terms to the left:

18x^2-(-9x)=0

We get rid of parentheses

18x^2+9x=0

a = 18; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·18·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*18}=\frac{-18}{36}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*18}=\frac{0}{36}
=0
$